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endriko
16th of October 2003 (Thu), 09:52
I sometimes need to charge my Canon G3 camera in a place without AC power. I have 4 quite powerful 6V batteries and I can select voltage output from 1,2V to 24V in 1,2V steps. I plan to select the correct voltage and polarity and plug it directly to camera's "DC IN" hole.

The "DC IN" hole on camera displays 9,5V as necessary voltage. As I can select the voltage in 1,2V steps I can't get 9,5V exactly but 9,6V (or 8,4V). Actually the voltage coming out of the batteries could be a little more when the batteries are full. I have a multimeter so I can check the exact voltage and polarity.

Could there be any risks charging the camera this way? Is it recommended to use slightly lower voltage (8,4V) rather than slightly higher voltage (9,6V)? Could slightly lower DC voltage do any harm to the camera? Of course I follow the polarities carefully.

I have charged my laptop with this method before and it works fine. My laptop requires 18,5V DC power and I have used 18V and 19,2V without any problem. Could the same method work with the camera or are there any additional risks?

yallcome
17th of October 2003 (Fri), 06:16
Hey, 9.6 volts is closer to 9.5, so I'd stick with that.

How did you figure out the proprietary plug? What is the schema on that thing and can it be bought separately as a standard size. I had thought about making an external battery pack for my G3, but haven't had the time to mess with it.

You give me the info and I'll be halfway there! :-)

m2

nomel
20th of October 2003 (Mon), 20:35
yallcome wrote:
Hey, 9.6 volts is closer to 9.5, so I'd stick with that.

How did you figure out the proprietary plug? What is the schema on that thing and can it be bought separately as a standard size. I had thought about making an external battery pack for my G3, but haven't had the time to mess with it.

You give me the info and I'll be halfway there! :-)

m2


The pinout for the power plug is on the power adapter!

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