swldstn wrote in post #16047793
Own both a CP-E4 that I had for my Canon flashes and just got a CL-180 with the 4500 battery pack (also with the Canon cable).
OK, the 4500 is 4500 mAh and according to the doc runs at 11.1V
My CP-E4 has 8 x 2000 mAh Eneloops that are probably 4 x 2 configuration so the operating voltage is maybe 6V = 1.5V x 4 and the power would be (4 x 1.5V) x (2 x 2000mAh) and would be 24000 Wh. Or maybe at a different voltage? Anyone know.
So the CL-L4500 is 11.1 x 4500 = 49950 Wh
The CP-E4 then is about have the power. Ok.
I think you will find that the Canon CP-E4 is a straight run of 8 AA cells in series rather than the 4x2 configuration you mention. This 8 cell daisy-chain is the widely used arrangement (Yongnuo, JJC, iShoot, Uwink, etc., etc). As far as I'm aware, but please don't take this as an absolute, only the Pixel TD-38x series uses two banks of 4 AAs. Different internal circuitry hence it's an independant new design and not a slavish copy. The big advantage to users is that with the Pixel design, if one of the 8 cells fails then only 1 bank of 4 is out of action and you still have the other bank of 4 cells to operate the pack, albeit marginally slower. With the 8-in-series arrangement, if one cell fails then so does the whole pack.
In either case, the output voltage as demanded by the external power port circuitry in the flash unit is in the 300-330v region - I've never seen any published figures for specific values.
If you take a set of XYZ batteries and connect them in SERIES (ie +ve to -ve terminal in a chain), the voltage is the sum of the voltages of each cell. Hence 8 AA rechargeables (of 1.2v nominal) in series would be 9.6v (8x1.2v). The CAPACITY would remain the same. So your 8 Eneloops would give you 9.6v but still only 2000mAh capacity. The alternative, connected in PARALLEL, wouldn't increase the VOLTAGE but you would then get accumulated capacity - you'd get 1.2v output but 16,000mAh capacity. (Circuits with batteries/accumulators in parallel aren't all that common in consumer level appliances these days.) You don't get both figures increasing at the same time. Brief overview of series and parallel circuits here if you're interested - but it's only a brief overview and not definitive.
So, going back to your particular instances:
These values are then input into the voltage-multiplying circuitry within each individual power pack
- Your CP-E4 power source (the 8 AA batteries) will give you initially 9.6 volts but still 2000mAh capacity.
- Your Godox or Cheetah will give you initially the 11.1 volts (3 Lithium cells of 3.7v each, in series) and the 4500mAh capacity as stated.
to raise the voltage
to the required level. The storage capacity remains the same in either case. This also explains why, to cope with the differing demands of various Metz units, the Mx lead ONLY works with specified units. As Canon, Nikon and Sony have been in the flash business a much shorter time than Metz, their demands are unified across each maker's range of units (where there even are external power ports, of course)
. Canon requirements may be different to Nikon requirements may be different to Sony requirements - there are variations within the Metz range which require further modification of the final voltage depending on the individual model. This drives the need for (eg) a Quantum CM4 with it's little box in the cable to power a Metz 45CL4 or a Quantum CM54 cable with a different controller box if running a Metz 54MZ4i. However, any (eg)
Canon flash which has an external power port should run with the Cx cable without further modification. Likewise Nikon, likewise Sony.
Although your calculations are all based on a false premise, the relationship between the values remains right in that the Cheetah L4500 has very roughly twice the capacity of a CP-E4. Highly dubious calculations but the right comparitive answers!