lightfighter6 wrote in post #16548889
My nephew's 1st birthday party is coming and my brother asked me to take pictures. the reception place is pretty big and dark not well lit.i have 430exII but sometime the back ground is to dark.
i can't bounce it too because of high ceiling, i'm thinking about getting a decent not to high end or expensive Strobe lights, well build and will do the job.
http://www.bhphotovideo.com …ing/ci/22522/N/3988592069
My gear check my sig.
If you have too high of a ceiling, the background will always be darker than the closer subject....because of the Inverse Square Law of intensity falloff. A more powerful flash will NOT reduce the darkness of the background relative to the foreground subject when flash is not bounced off the ceiling.
Let us assume you are shooting at ISO 100 with 32mm 'normal' lens on your APS-C camera.
- With 430EX, your 'normal lens' guide number is 112. So at f/4 the light will reach only as far as 28; but your subject is at 14 (112/4=28)'. So ETTL flash metering tells the 430EX to output less light (not full power) so your subject at 14' is properly exposed. If we compare the illumination at 28' vs. the illumination at 14', 28' is twice as far as 14' and therefore it is 1/4 the power (-2EV) in brightness.
- Let's substitute a 580EX...with 580EX, your 'normal lens' guide number is 138. So at f/4 the light will reach a bit farther but only as far as 34.5' (138/4=34.5); but your subject is at 14'. So ETTL flash metering tells the 580EX to output less light (not full power) so your subject at 14' is properly exposed. If we compare the illumination at 28' vs. the illumination at 14', 28' is twice as far as 14' and therefore it is 1/4 the power (-2EV) in brightness.
It matters not that the 580EX can reach farther than the 430EX (34.5' vs. 28')...the light at 28' is always -2EV dimmer than the light at 14' from a
directly aimed speedlight. Double the distance = 1/4 the power...the Inverse Square Law