It's already 2AM: 22nd Edition... Wait... how is it still 2AM?

20droger wrote in post #13726840
Hmmm. You do like math, don't you?

It's my best language!

laxlife1234 wrote in post #13726725
So... I guess I'm going on a date Friday. My friend is setting me up with one of her friends

Cool. Leave the camera... at least until AFTER the 3rd date.

*sigh* wrote in post #13726751
You guys are weird.

Figuring that out just NOW?

Try this little fun problem.

Start with a basic assumption: x is identical to y. Therefore:

x = y

Multiply by x:

x² = xy

Subtract y²

x² - y² = xy - y²

Factor:

(x + y)(x - y) = y(x - y)

Divide by (x - y)

x + y = y

However, since x is identical to y, substitute y for x:

2y = y

Divide by y:

2 = 1

Where's the error?

Blurr Cube wrote in post #13726878
Cool. Leave the camera... at least until AFTER the 3rd date.

And then bring the video cam with the bow chica wow wow music playing in the background for mood.

20droger wrote in post #13726767
Mathematicians, engineers, and accountants: they all play with numbers, but not quite in the same way.

When asked what 2 plus 2 equals:

a mathematician will break into a thirty-minute monolog on the theory of numbers, ending with "and therefore, 2 plus 2 most often equals 4";

an engineer will whip out his (RPN) calculator, tap it four times, and say "4"; and

an accountant will look around to make sure you're alone, put his arm over your shoulders, and very quietly ask, "What would you like it to be?"

Heh. The accountant sounds like some tax preparers too.

Harm wrote in post #13726851
quello che non capisci? Stavo dicendo loro di prestare attenzione al fatto che avevo già postato un collegamento della conversazione.

Uh... non capisco.

20droger wrote in post #13726889
Try this little fun problem.

Start with a basic assumption: x is identical to y. Therefore:

x = y

Multiply by x:

x² = xy

Subtract y²

x² - y² = xy - y²

Factor:

(x + y)(x - y) = y(x - y)

Divide by (x - y)

x + y = y

However, since x is identical to y, substitute y for x:

2y = y

Divide by y:

2 = 1

Where's the error?

O.o not even gonna bother. my favorite equation would be...

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Harm wrote in post #13726811
You guess?

At least it is one step further than Nick (sorry, couldn't help that one...) got

Ba dum tish.

Blurr Cube wrote in post #13726857
2 art classes? Take 'em over the weekends.

i cant do weekends. i cant stand long classes. i rather split them between 2 days a week ;p

and I might could get away with not having to go to the classes. I've taken a few classes at another college so I'll need to request transcripts and hope I passed and that it will qualify.

if not.. I shall take a photo class and life drawing class. either that or take two photo class (1&2) since i'm just gonna do 1 class a semester.

20droger wrote in post #13726889
Try this little fun problem.

Start with a basic assumption: x is identical to y. Therefore:

x = y

Multiply by x:

x² = xy

Subtract y²

x² - y² = xy - y²

Factor:

(x + y)(x - y) = y(x - y)

Divide by (x - y)
x + y = y

However, since x is identical to y, substitute y for x:

2y = y

Divide by y:

2 = 1

Where's the error?

Divide by 0.

DTBaan wrote in post #13726953
i cant do weekends. i cant stand long classes. i rather split them between 2 days a week ;p

and I might could get away with not having to go to the classes. I've taken a few classes at another college so I'll need to request transcripts and hope I passed and that it will qualify.

if not.. I shall take a photo class and life drawing class. either that or take two photo class (1&2) since i'm just gonna do 1 class a semester.

Won't classes interfere with your work hours? Or are you gonna take night classes?

Blurr Cube wrote in post #13726956
Divide by 0.

Güt!

20droger wrote in post #13726889
Try this little fun problem.

Start with a basic assumption: x is identical to y. Therefore:

x = y

Multiply by x:

x² = xy

Subtract y²

x² - y² = xy - y²

Factor:

(x + y)(x - y) = y(x - y)

Divide by (x - y)

x + y = y

However, since x is identical to y, substitute y for x:

2y = y

Divide by y:

2 = 1

Where's the error?

When you divide by zero, things dont add up, actually diviiding by zero gives infinity
Dividing by x-y is dividing by zero, subtracting the same number from the number is zero