but if you took a picture at 50mm, f2 and 6 ft away on a crop, and on a FF camera...would the larger sensor size really give you shallower DOF...
no...it'd actually give you more DOF...
^
OK folks, here goes...
- Shooting 50mm FL on APS-C from 20' away a yardstick target, our frame captures an area of 6' x 9' and a 3' tall yardstick is 50% of the height of the frame. We magnify the 14.9x22.3mm frame by 13.6x to make the 8x10" print (the standard by which DOF calculators assume). The yardstick is 4" high on the 8" print. At f/2 our DOF zone is from 18.6' - 21.6', or 3.0' deep.
- Shooting 50mm FL on FF from 20' away, our frame captures an area of 9.5' x 14.3' and a 3' tall yardstick is 32% of the height of the frame. We magnify the 24x36frame by 8.5x to make the 8x10" print (the standard by which DOF calculators assume). The yardstick is 2.56" high on the 8" print. At f/2 our DOF zone is from 17.8' - 22.7', or 4.9' deep.
The DOF is greater on the FF camera simply because the subject is smaller in the print, when both cameras shoot with same lens from same camera position and both images are magnified proportionate to the actual image area to fill the standard 8x10" print used in DOF calculators. Size of format does enter the DOF consideration due to the magnification of the initial image to make the 8x10" print.
Stated differently, 50mm on FF is a 'normal' lens and a subject fills less of the frame. 50mm on APS-C is a 'short tele' and a subject fills more of the frame. And 'tele FL' has 'less DOF' than a 'normal FL' lens, just as everyone expects. But really, ultimately DOF is associated with the magnitude of the subject within the 8x10 print...in addition to FL, distance, aperture, and format size already pointed out....which is why DOF calculations are meaningless if you are looking at a larger/smaller print size than 8x10"

