nzl-g3user wrote:
Hi, since I am new to the 10D (coming from the G3) I have a question about taking shots of stars.
With the G3 I could point the camera in to the sky and with an shutter speed of 15" I would get nice points of lights, however I have noticed that with the 10D the points of lights at 15" become small streaks
Why? I am using the same tripod that I used for the G3 so why is this happening?
I took a picture of the Big Dipper last week in a moonlit sky, and saw no discernable star trails with a 30-second exposure. I used f/5.6 at ISO 800, and can see stars down to magnitude 5 or 6 in the image. The Moon lit up the foreground and sky enough to make the image look nearly like daylight, and it is rather surreal to see stars in an otherwise daylight-looking image.
But I was using a 14mm lens to get a very wide sky field. The longer the lens, the more the movement.
Think of it this way. If a normal lens (28mm on a 10D) has a 45-degree field of view, then one pixel subtends an angle of about 0.0125 degrees, or 45 arc-seconds. Now, there's a convenient equation: the angle of view of the lens in degrees is equivalent to the number of arc-seconds of angle for each pixel. (This convenient relationship is because the there are 3600 pixels diagonally across the 10D frame, and 3600 arc-seconds in a degree).
If the sky rotates 360 degrees in a day (it isn't that exactly, of course, but it's close enough for this calculation), then 24 hours means a sky movement of 28,800 pixel-widths. Thus, one pixel width of sky movement happens every three seconds with a normal lens. With a normal lens, you will therefore get streaks five pixels long in 15 seconds. Remember that the brighter stars will flare in the lens, and this flare will cover up some streaking. My bright Big Dipper stars, even with the 14mm lens, were spots three or four pixels around, and that's probably why I didn't see any streaking.
It is not mirror-slap, by the way. Vibration from mirror slap will only last a tiny fraction of a second, and therefore will only affect images of a tiny fraction of a second. With a 15-second exposure, the part of the exposure made during that vibration would not even be visible in the image, except for point source lit well enough to be exposed visible in a small fraction of a second, and those would flare out completely in a 15-second exposure.
Rick "doing the arithmetic" Denney