I can't find the answer to these two questions anywhere...
QUESTION 1.
Let's say I have three 580EX's; one master on the camera, one slave in group A, and one slave in group B. I am shooting in fully automatic ETTL-II mode and have set the A:B ratio to say 4:1.
If I have the on-camera master set to NOT fire, then all is good and I understand my light ratios, A=4 and B=1.
BUT, if I have the on-camera master set to fire, what is the ratio of it's contribution of light to the picture? It is contributing something but it is not set by me.
QUESTION 2.
Same situation and question as above but in Manual mode instead of ETTL-II automatic. From the master you set the ratios of each slave but you only set the master to fire or not to fire.
I hope this makes sense. I has been bugging me for some time now.

