Math equation

Sorry to bother you guys. I read a math equation on here a few days back about lens and the xti or I believed referred to as the 1.6 crop body. It the equation to use with a lens to get the actual field of view or something. Can someone post what it was again and exactly what it does. I have done every kind of search using 500 different combinations to find it and come up empty.

Thanks

It is simple, just multiply the focal length of the lens you are looking at by 1.6, this gives you the effective focal range of the lens. This is the result of the digital sensor on a crop camera being less than full 35mm frame size.

If you multiply the focal length of the lens by 1.6 then you get the equivalent reach and field of view that you would have had, if you were using the same lens on a 35mm film slr (or a full frame digital). So for example, if you use a 70-200mm lens on a 1.6 crop body, it behaves the same as a 112-320 would on a 35mm camera.

Thanks guys. You are quick. I really appreciate it.

Yep, it's the 35mm equivalent FOV that you are getting when you take the 1.6x Crop Factor into account.

You are not capturing more detail, since the CF doesn't affect "magnification"...so 200mm is 200mm whether it's on a crop or FF. It's the FOV that is different.

Confusing?
Heck Yeah!

nicksan wrote in post #3539786
Yep, it's the 35mm equivalent FOV that you are getting when you take the 1.6x Crop Factor into account.

You are not capturing more detail, since the CF doesn't affect "magnification"...so 200mm is 200mm whether it's on a crop or FF. It's the FOV that is different.

Confusing?
Heck Yeah!

This should be required reading for all camera store employees.
Great expalnation