5D rigged to a kite

aLFaDaRK wrote in post #4000666
Well the force of gravity is (-9.8 )(2 kg) = -19.6 N. FNet must be > 0 to accelerate upwards, so the force upwards must be above 19.6 N.

aLFaDaRK wrote in post #4000666
Well the force of gravity is (-9.8 )(2 kg) = -19.6 N. FNet must be > 0 to accelerate upwards, so the force upwards must be above 19.6 N. I have no idea how much wind you would need though for a 40-sq foot kite in order to give that much force, but it's a considerable amount. (I'll be totally honest and say that I forget the formulas that would let me find that out :P)

Anyway, very neat shots, my insurance would cover it... but I don't dare to try anyway :P

aLFaDaRK wrote in post #4000666
Well the force of gravity is (-9.8 )(2 kg) = -19.6 N. FNet must be > 0 to accelerate upwards, so the force upwards must be above 19.6 N. I have no idea how much wind you would need though for a 40-sq foot kite in order to give that much force, but it's a considerable amount. (I'll be totally honest and say that I forget the formulas that would let me find that out :P)