pete.mod wrote in post #4271397
Yes, from what I have read, CMOS is less expensive to produce than CCD.
Okay, so if the "light wells" are smaller and they collect less light, how does that contribute to noise? Is it because the sensor doesn't collect accurate data about the light hitting it and spits out a faulty signal?
It's a physics/physical property that shows the amount of noise is inversely proportionate to the amount of light collected by a receptor. There is a good discussion of this, with examples, at this site
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Also, I read that CCD and CMOS work by transforming photons to electrons, like a solar panel. So if you crank up the ISO, it means you are also cranking the power being fed to the sensor right? How does that make it more sensitive when it is collecting light to produce electricity in the first place?
When you turn up the ISO you are, in essence, amplifying the light collected at your given exposure to "look like" you got more light. It's not "real" sensitivity in the sense that film is more sensitive. It's electronic amplification. Noise becomes increasingly noticeable at higher ISOs because you are amping less and less "good" signal to produce an acceptable equivalent exposure: the less "good" light that the pixel sites collect the more noise comes up proportionately. You see the same thing if you have an image at any ISO with deep shadows and try to amp up the shadows in post-processing.
I'm sorry if this is too technical, I'll be doing more searching on Google, I just thought someone here might know. If I find out why, I'll post it here for those that are interested.
Check out the site I pointed you to. There is a lot of testing, analysing, discussing and referencing going on there!