superdiver wrote in post #5492076
What you have said make perfect sense, except for this part... Like René, it confuses me.
When I read this I read (in my words, obviously the problem here...lol), is "the more light that falls on the sensor the more noise is produced", but that would be contrary to what you are explaining, or what am I missing?
Everything else makes sense, but this just seems to go against what everything else says...
What you have said make perfect sense, except for this part... Like René, it confuses me.
When I read this I read (in my words, obviously the problem here...lol), is "the more light that falls on the sensor the more noise is produced", but that would be contrary to what you are explaining, or what am I missing?
Everything else makes sense, but this just seems to go against what everything else says...
20droger wrote:
This is because those portions of the sensor receiving a greater amount of light simply override the noise with brightness.
This is because those portions of the sensor receiving a greater amount of light simply override the noise with brightness.
If I may express it a bit differently, the key to understanding this is S:N, the signal to noise ratio. As exposure increases, shot (sensor) noise increases but the quantity of image data increases faster, so although the absolute amount of noise is greater, the relative amount (relative to image data) is less. The noise is therefore unseen in the highlights.
