Dermit wrote in post #5535810
Is this true? Do you really have to add in the x1.6? I mean a 200mm lens on a 1.6 sensor is NOT a 320mm lens. The only thing that happens is that the sensor only sees the same field of view (FOV) as a 320mm lens. So it is NOT magnifying the image the same as a 320mm. And camera shake only becomes more amplified when an image is more magnified, which in this case it is NOT. A 200mm lens on a 1.6 sensor camera is still a 200mm lens. Of course I could be missing something here, so if I am let me know.
With IS on I have successfully shot down as low a 1/30 shutter on my 70-200 IS.
Dermit wrote in post #5535925
Actually I have an old D60, which is a 1.6 factor sensor and, no, the image is NOT magnified, it is cropped. I could emulate a 1.6 factor sensor on my 5D by taking a picture and then crop the image to only include what the 1.6 sensor would see.
A 1.6 sensor seems like a magnification because we see less field of view, which is what longer focal length lenses do. But in this case it sees narrower because the sensor is smaller, not because it is more magnification.
This is a subject I have been curious about so i am not saying i am right or wrong, just that I would like to understand it. So far I don't understand how given the exact same focal length you can get more actual magnification just because the sensor is smaller.
Dermit wrote in post #5536017
Sorry, I am still not there. I think I understand what you are trying to say, but it's not playing well with the issue. One thing i agree on is the closer pixels are together the more critical camera shake becomes. But that is a resolution issue and the same would be true for a 1.6 or a full size sensor. If both had identical pixel pitch the focal length and crop factor still would not matter (in my head) in regards to hand holding the camera and shutter speed. The exact same image transmits through the lens and falls on the focal plane of the camera. It's just that the 1.6 sensor is only capturing a smaller center portion of that projected image. True? Or am i way off base, or just not getting it?
The 1/focal length rule-of-thumb was adopted many years ago for the 35mm film format (size of the film frame or sensor in a camera). I do believe it originated with medium-format cameras, but the fact is that it's been an accepted rule-of-thumb for 35mm film cameras for at least four decades that I know about.
The difference between shooting with a 35mm film (or "full-frame" DSLR) camera and an APS-C camera is that the image from the APS-C camera must be enlarged more to fill the same sized print. For example - if you were to make an 8-inch by 12-inch print from a 35mm film negative (or from a 5D, for example), you'd have to enlarge the in-camera image by a factor of 8.47 (in each direction). If you were to make the same 8-inch by 12-inch print from the image taken with a 40D, you'd have to enlarge the in-camera image by a factor of 13.55 (again, in each direction).
If you had "X" amount of physical motion of the camera/lens (remember it's the SAME lens on both cameras) that resulted a blur that is .05mm wide IN THE CAMERA, you would have a blur on the print from the 35mm camera that is .423mm wide and a blur on the print from the 40D that is .678mm wide.
From this, you can see that to match the blur of the print made from the 35mm camera you would have to shorten the IN-CAMERA blur by a factor of 1.6. How do you do that? You would have to shorten the shutter speed time by a factor of 1.6.
Thus, to keep the rule-of-thumb the same for different format cameras, you need to add the "crop factor" (or whatever you want to call the ratio of the two format sizes) to the rule-of-thumb. This, of course, assumes that the rule-of-thumb works for one of the formats involved.
A rule-of-thumb is a generalization for the average population, and for any individual the value may be high or low. That does not change the fact than you cannot apply the same formula to different camera formats and have the same result. I hope you understand my math above that proves this.