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Thread started 31 Jan 2009 (Saturday) 11:49
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ICee
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Jan 31, 2009 11:49 |  #1

Can anyone tell me the equation to work out if I crop a 8.2MP image down to 50% of it's original size how many pixels will be left.

logic say 4.1 but I thought I read somewhere that it doesn't work like that.

Thanks in advance for your answers.




  
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EOS_JD
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Jan 31, 2009 12:13 |  #2

My 40D produces 3888 x 2592 pixels That is 10,077,696 pixels.

Taking the image to 50% means you half the height and the width so 4x reduction and size is 1944 x 1296 or 2,519,424 (2.5Mp)

To halve the No of pixels you should crop only one side by half


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12mnkys
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Jan 31, 2009 12:15 |  #3

On an 8.2 MP camera...we can use the 30D for this example... The pixels work out like this...

3507 pixels on long end
2338 onshort end

3507 x 2338 = 8,199,366 Pixels or 8.2 MP

If you crop out 50% of the pixels on both the long and short end:

1754 pixels on the long end
1169 pixels on the short end

1754 x 1169 = 2,050,426 pixels or 2.1 MP roughly

If you were to just crop half of the picture:

1754 Pixels
2338 Pixels

1754 x 2338 = 4,100,852 pixels or 4.1 MP

Does that help at all??

MK


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vincent_su
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Jan 31, 2009 12:18 |  #4

ICee wrote in post #7226778 (external link)
Can anyone tell me the equation to work out if I crop a 8.2MP image down to 50% of it's original size how many pixels will be left.

logic say 4.1 but I thought I read somewhere that it doesn't work like that.

Thanks in advance for your answers.

If the 50% crop is based on diagnal length, you should end up with 1/4 of the pixels, 2.05 MP.

Oops, I did not see last post. Go with 12Mnkys.


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ICee
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Jan 31, 2009 12:35 |  #5

Thanks guys that's what I was trying to get.

Cheers.




  
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12mnkys
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Jan 31, 2009 12:36 |  #6

No problem! Good Luck!


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