[Lightroom] - What is my average focal length?

Is there a feature in Lightroom where you can select a particular lens or shooting date and have Lightroom calculate your average focal length?

This would be very helpful for determining which prime to buy.

It would also be nice to be able to filter by focal length as per Bridge but apparently Adobe is too good to put that feature into Lightroom.

mdaniel wrote in post #8622149
Is there a feature in Lightroom where you can select a particular lens or shooting date and have Lightroom calculate your average focal length?

This would be very helpful for determining which prime to buy.

Lightroom can't do that. Try Exposure Plot or Smart Photo Statistics.
If I remember correctly, those programs don't support RAW. I think I used to export tiny JPG files to a folder then run the program on that folder.

http://www.wega2.vande​l.nl/
http://www.softsymphon​y.com/photostat_descr.​htm

Thanks Mark. I'll give that a shot.

If you have Photoshop you can get the information you want through Adobe Bridge.

Yossarian22 wrote in post #8622170
It would also be nice to be able to filter by focal length as per Bridge but apparently Adobe is too good to put that feature into Lightroom.

You can search a specific FL used:
(Note it seaches for FL, not lens used.)

René Damkot wrote in post #8626449
You can search a specific FL used:
(Note it seaches for FL, not lens used.)

This is OK if you just want to browse through a few photos that might be of a certain focal length, but it wouldn't be good enough to evaluate your most used focal length.

This method only allows you to see one focal length at a time. Specialized software will let you see all focal lengths in a bar graph and it will let you group by intervals if you want. For example, I could tell Exposure Plot to break down my shots into 15-25mm, 25-35mm, etc and show one bar for each group.

Also, typing "20" into that searchable Exif field will give you 20mm, 120mm, and 200mm. Better than nothing, but there are better (free) options out there.